(x-1)(x+3)=x^2+4

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Solution for (x-1)(x+3)=x^2+4 equation: 



(x-1)(x+3)=x^2+4

We move all terms to the left:

(x-1)(x+3)-(x^2+4)=0

We get rid of parentheses

-x^2+(x-1)(x+3)-4=0

We multiply parentheses ..

-x^2+(+x^2+3x-1x-3)-4=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+3x-1x-3)-4=0

We get rid of parentheses

-1x^2+x^2+3x-1x-3-4=0

We add all the numbers together, and all the variables

2x-7=0

We move all terms containing x to the left, all other terms to the right

2x=7

x=7/2

x=3+1/2

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